X^2-49x+48=0

Solution for X^2-49x+48=0 equation:

X^2-49X+48=0

a = 1; b = -49; c = +48;
Δ = b2-4ac
Δ = -492-4·1·48
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-47}{2*1}=\frac{2}{2}
=1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+47}{2*1}=\frac{96}{2}
=48
$